if (1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz..
Arun Dutt Kaushik
August 19, 2020
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(1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz = ? Solution: Please don't forget to share your valuable fee...
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