if (1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz.. - Math Traders

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if (1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz..

(1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz = ?

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(1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz = ?

(1/x)+(1/y)+(1/z)=0 and x+y+z = 9 then x^3+y^3+z^3-3xyz = ?
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