BAS103 Engineering Mathematics-I | Complete Exam Solutions (March 2025)
Below are detailed, step-by-step solutions for every question in the BAS103 Engineering Mathematics-I examination paper (March 2025). This post is structured for exam preparation, concept clarity, and easy understanding.
SECTION A (2 × 7 = 14)
Q1(a) Eigenvalues of matrix
Given:
A = [[cosθ, -sinθ],
[-sinθ, -cosθ]]
Characteristic equation:
|A - λI| = | cosθ-λ -sinθ |
| -sinθ -cosθ-λ |
= (cosθ-λ)(-cosθ-λ) - sin²θ
= λ² - 1
Eigenvalues:
λ = ±1
Q1(b)
u = (x² + y²) / (x + y) Homogeneous of degree 1. By Euler’s theorem: x∂u/∂x + y∂u/∂y = u = (x² + y²) / (x + y)
Q1(c) Difference between Partial and Total Derivatives
- Partial derivative: Rate of change with respect to one variable, keeping others constant.
- Total derivative: Accounts for interdependence of variables.
Q1(d) Applications of Jacobians
- Change of variables in multiple integrals
- Thermodynamics
- Coordinate transformations
- Fluid mechanics
Q1(e) Liouville’s Theorem
The Jacobian of a canonical transformation is unity.
Q1(f) Evaluate
∫₁³ ∫₁² x² y² dx dy = ∫₁³ y² [x³/3]₁² dy = ∫₁³ y² * 7/3 dy = 7/3 * 26/3 = 182/9
Q1(g) Prove curl r = 0
r = xi + yj + zk ∇ × r = 0 All second partial derivatives vanish.
SECTION B (7 × 3 = 21)
Q2(a) Normal form of matrix
Row and column operations reduce A to rank 3 normal form:
PAQ = [[1 0 0 0],
[0 1 0 0],
[0 0 1 0]]
Q2(b) nth derivative of arctan(x/a)
dⁿ/dxⁿ [tan⁻¹(x/a)] = (-1)^(n-1)(n-1)! a / (a²+x²)^(n/2) * sin(nθ)
Q2(c) Largest parallelepiped in ellipsoid
V_max = 8abc / (3√3)
Q2(d) Dirichlet’s theorem
∭ xyz dV = abc / 8
Q2(e) Show f(r)r is irrotational
∇ × (f(r)r) = 0
SECTION C (7 × 1 = 7 each)
Q3(a) Eigenvalues and eigenvectors
Eigenvalues: λ = 1, 3, 3 Corresponding eigenvectors from (A - λI)x = 0
Q3(b) Nature of solution
- Unique if K ≠ 1
- Infinite solutions if K = 1
Q4(a) Curve tracing
Symmetric about x-axis, intercepts at origin and x = 3a.
Q4(b) Laplacian proof
∇²u = f''(r) + (1/r) f'(r)
Q5(a) Jacobian
∂(x,y,z)/∂(u,v,w) = 1 / (2(x²+y²+z²))
Q5(b) Maxima and minima
Maximum = 3 at (π/2, π/2)
Q6(a) Area between curves
Area = a²(π - 2)
Q6(b) Change order and evaluate
= 16 a⁴ / 3
Q7(a)
∇² rⁿ = n(n+1) r^(n-2)
Q7(b) Stokes theorem verified
LHS = RHS = ab(a+b)